Grade 12 Math · Problem type

Circles through the pole

Use this for “Graph r = 6 cos θ: find r at θ = 60°, the center and the radius.”

Diagram

0°30°60°90°120°150°180°210°240°270°300°330°2468r = 6 cos θθ(3, 60°)
r = 6 cos θ: a circle of diameter 6 through the pole, θ from 0° to 180°.
(r, θ) = (3, 60°)
This is an example. Type your own values to start a new problem.
r
=
a
cos
θ
°
h
Center x-coordinate
calculated
R
Radius
worked out (not typed)

Formulas

r
=
a
×
cos(
θ
°)
3 = 6 × cos(60°)
h
=
a
2
3
=
6
2
R
=
|
a
|
÷
2
3 = |6| ÷ 2

Assumptions

•
r = a cos θ is a circle through the pole with diameter |a| along the x-axis.
•
Times r: r² = ar cos θ, so x² + y² = ax, a circle centered at (a/2, 0) with radius |a|/2.
•
The whole circle is drawn as θ runs from 0° to 180°; past 90° r is negative.

Step-by-step

WE KNOW
a = 6, θ = 60°
FIND
directed distance r (r), center x-coordinate (h), radius (R)
Step 1 · Find directed distance r (r)
Use r = a × cos(θ°)
Put
θ
into
the
curve’s
equation.
r
=
6
×
cos(60°)
r
=
6
×
0.5
r
=
3
Step 2 · Find center x-coordinate (h)
Use h = a ÷ 2
The center is halfway along the diameter from the pole, on the x-axis.
h
=
6
2
h
=
3
Step 3 · Find radius (R)
Use R = |a| ÷ 2
The radius is half the diameter.
R
=
|6|
÷
2
R
=
6
2
R
=
3
Check
Put the numbers back in. Both sides should match.
3 = 6 × cos(60°) ✓
3
=
6
2
✓
3 = |6| ÷ 2 ✓
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