SME
Organic Chemistry I
Alkenes and alkynes
Use this for “Propene reacts with HBr. Is the product 1-bromopropane or 2-bromopropane?”
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Where does the new group (not the H) go?
Tap a card, then tap its group.
Where a cation forms, it forms on the more substituted carbon, and the new group bonds there.
Assumptions
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Each reagent adds to an unsymmetrical alkene such as propene or 2-methylpropene, or to an alkyne where the card says so.
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The more substituted carbon of the C=C is the one with more carbons bonded to it.
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A cation is more stable on a carbon with more carbons around it: tertiary over secondary over primary.
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An alkyne follows the same rule as an alkene, one equivalent of the reagent at a time.
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