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Grade 10 Science · Problem type

Effusion: Graham’s law

Use this for “Helium (4.00 g/mol) and argon (39.95 g/mol) leak from one tank. Which escapes faster, and how many times as fast?”

Diagram

pinholeRate of escape, ∝ 1/√MHe (4)3.16×Ar (39.95)1×
rate
of
He
rate
of
Ar
=
√(
39.95
4
)
=
3.16
The lighter He moves faster and escapes 3.16 times as fast as Ar.
At one temperature every gas has the same average kinetic energy, so lighter molecules move faster.
This is an example. Type your own values to start a new problem.
r
=
M₂ (g/mol)
M₁ (g/mol)

Formulas

r
=
√
M₂
M₁
3.16
=
√
39.95/4

Assumptions

•
Both gases are at the same temperature, so their molecules have the same average kinetic energy.
•
Lighter molecules move faster, so they find the pinhole more often.
•
rate₁ ÷ rate₂ = √(M₂ ÷ M₁).

Step-by-step

WE KNOW
M₁ = 4 g/mol, M₂ = 39.95 g/mol
FIND
how many times as fast gas 1 escapes (r)
Step 1 · Find how many times as fast gas 1 escapes (r)
Use r = √(M₂/M₁)
Graham’s law: the rate goes as 1 over the square root of the molar mass.
r
=
√
39.95/4
r
=
√
9.9875
r
=
3.16
Check
Put the numbers back in. Both sides should match.
3.16
≈
√
39.95/4
✓
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