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Climatology · Problem type

Peak wavelength of the Sun’s and Earth’s light

Use this for “At what wavelength does the Sun, at 5,772 K, shine brightest, and Earth, at 288 K?”

Diagram

← longer wavelengthshorter wavelength →RadioMicrowaveInfraredUVX-rayGamma1 km1 m1 mm1 µm1 nm1 pm700 nm400 nmvisible lightλₘₐₓ = 0.5021 μm
λₘₐₓ = 0.5021 μm: visible light (green).
This is an example. Type your own values to start a new problem.
λₘₐₓ (μm)
=
2,898
μm·K
T (K)

Formulas

λₘₐₓ
=
2,898
T
0.5021
=
2,898
5,772

Assumptions

•
Both glow as black bodies; λₘₐₓ is only the brightest wavelength of a broad spectrum.
•
Wien’s constant b = 2,898 μm·K, so λₘₐₓ in μm is 2,898 over T in kelvins.
•
The Sun peaks in visible light and Earth near 10 μm, so greenhouse gases act on the outgoing infrared.

Step-by-step

WE KNOW
T = 5,772 K
FIND
peak wavelength (λₘₐₓ)
Step 1 · Find peak wavelength (λₘₐₓ)
Use λₘₐₓ = 2,898 ÷ T
Wien’s law: the hotter the body, the shorter its brightest wavelength.
λₘₐₓ
=
2,898
5,772
λₘₐₓ = 0.5021 μm
Check
Put the numbers back in. Both sides should match.
0.5021
=
2,898
5,772
✓
Topic check
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